Differentiator
Consider the output across the resistor at low frequency i.e.,
- .
This means that the capacitor has time to charge up until its voltage is almost equal to the source's voltage. Considering the expression for again, when
- ,
so
Now,
- Circuit
output
For C=0.1u R=1k |
Since RC=0.1ms . 5RC=0.5ms which is less compared to pulse width of 2ms. The resistor will lose its voltage very soon. Initially V(R)=2v because capacitor acts as short. As RC is very small.Capacitor gets 2v at the end of 0.5ms.
Undesirable output
For C=1u R=1k |
SEE Video here
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