1) A music signal with frequency components
from 50 Hz to 21000 Hz is Frequency modulated.
If the maximum allowed frequency deviation is 50 kHz. (i) What is the modulation index?
ii)What is the signal bandwidth usingCarson ’s rule?
Carson ’s
rule.
ii)What is the signal bandwidth using
Solution: i) Modulation index = frequency
deviation/modulating frequency = 50 kHz/21 kHz = 2.38
(ii) Bandwidth is 2 (modulating frequency +
frequency deviation) = 2 (21 kHz + 50 kHz) = 142 kHz
2)A 200 MHz carrier is frequency modulated by
a 10 V peak-to-peak signal of 10 kHz. The instantaneous carrier frequency
varies between 199.90 and 200.10 MHz.
Calculate (i)
The modulator sensitivity.
(ii)
The modulation index.
(iii)
The signal bandwidth using (i)
2 * Frequency deviation = 200.10 – 199.9 MHz = 200 kHz.
Frequency deviation = 100kHz
This is caused by a 10 V signal.
Therefore sensitivity is 100/10 kHz/V = 10 kHz/V
(ii)
The modulation
index is 200 kHz / 10 kHz = 20.
(iii)
BW = 2
(frequency of modulating signal + frequency deviation)
= 2
( fm + k * fd)
= 2
( 1 + b ) * fm
Using any of the above
BW
= 420kHz
3) A speech signal with frequency components
from 300 Hz to 4 kHz is Frequency modulated.
If the maximum allowed frequency deviation is 30 kHz
(i)
What is the modulation index?
(ii)
What is the signal bandwidth
using
|
(i)
Modulation index = frequency
deviation/modulating frequency = 30 kHz/4 kHz = 7.5
(ii)
Bandwidth is 2 (modulating frequency + frequency
deviation) = 2 (30 kHz + 4 kHz) = 68 kHz
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