Friday, October 18, 2013

Two capacitors Initially charged ,Popular question in Analog electronics




This is the Popular question in analog electronics. 
Lets see how this works

C1 is initially charged with 2volts and C5 is charged with 1 volts.
And there is a Resistor of 10k between the two capacitors.

Since C1 is at higher potential than C5 , current flows through 10k and voltage of C1 tends to drop and that of C5 will increase . The current will  stop flowing after both capacitor reach common voltage.
That common voltage can be found using the equation

V=Q/C

V=(C1v1+c5V2)/ (c1+c5) {Refer figure}
Substituting the values

V=(1u*2++0.5u*1)/ (1u+0.5u)
V=2.5u/1.5u

V=1.66v. which is the voltage across each capacitors




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